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0=12x^2+3
We move all terms to the left:
0-(12x^2+3)=0
We add all the numbers together, and all the variables
-(12x^2+3)=0
We get rid of parentheses
-12x^2-3=0
a = -12; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-12)·(-3)
Δ = -144
Delta is less than zero, so there is no solution for the equation
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